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Passing the Oracle 1Z0-829 Certification Exam can open the doors to exciting career opportunities for Java developers. Certified professionals are highly sought after by top companies and can command higher salaries. Java SE 17 Developer certification also demonstrates a commitment to professional development and continuous learning, which can help developers stay ahead of the curve in a fast-paced and constantly evolving industry.

One of the key benefits of obtaining the Oracle 1Z0-829 Certification is the validation of your skills and expertise in Java SE 17 development. Java SE 17 Developer certification is recognized globally and can help you to stand out in a competitive job market. It is also a valuable asset for those who are looking to advance their career within their current organization.

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Oracle 1Z0-829 (Java SE 17 Developer) Certification Exam is a globally recognized certification that validates the skills and knowledge of Java developers. Java SE 17 Developer certification exam is designed for developers who have a strong understanding of Java programming language and are willing to enhance their skills and knowledge to the next level. 1Z0-829 Exam focuses on various aspects of Java development, such as Java SE 17 features, Java I/O, concurrency, and JDBC.

Oracle Java SE 17 Developer Sample Questions (Q47-Q52):

NEW QUESTION # 47
Given:

Which two modifications enable the code to print Open Close?

Answer: B,D

Explanation:
The code given is a try-with-resources statement that declares a resource of type AutoCloseable. The resource is an anonymous class that implements the AutoCloseable interface and overrides the close() method. The code also has a print() method that prints the value of the variable s. The code is supposed to print "Open Close", but it does not compile because of two errors.
The first error is at line n1, where the anonymous class is missing a semicolon at the end of its declaration. This causes a syntax error and prevents the code from compiling. To fix this error, option B adds a semicolon after the closing curly brace of the anonymous class.
The second error is at line n2, where the print() method is called without an object reference. This causes a compilation error because the print() method is not static and cannot be invoked without an object. To fix this error, option E adds an object reference to the print() method by using the variable t.
Therefore, options B and E are correct and enable the code to print "Open Close".

NEW QUESTION # 48
Given the code fragment:

A. True:false:true:false
B. True:true:false:false
C. True:false:false:false
D. True:false:true:true

Answer: A

Explanation:
Explanation
The code fragment compares four pairs of strings using the equals() and intern() methods. The equals() method compares the content of two strings, while the intern() method returns a canonical representation of a string, which means that it returns a reference to an existing string with the same content in the string pool. The string pool is a memory area where strings are stored and reused to save space and improve performance. The results of the comparisons are as follows:
s1.equals(s2): This returns true because both s1 and s2 have the same content, "Hello Java 17".
s1 == s2: This returns false because s1 and s2 are different objects with different references, even though they have the same content. The == operator compares the references of two objects, not their content.
s1.intern() == s2.intern(): This returns true because both s1.intern() and s2.intern() return a reference to the same string object in the string pool, which has the content "Hello Java 17". The intern() method ensures that there is only one copy of each distinct string value in the string pool.
"Hello Java 17" == s2: This returns false because "Hello Java 17" is a string literal, which is automatically interned and stored in the string pool, while s2 is a string object created with the new operator, which is not interned by default and stored in the heap. Therefore, they have different references and are not equal using the == operator.
References: String (Java SE 17 & JDK 17) - Oracle

NEW QUESTION # 49
Given the code fragment:

abstract sealed interface SInt permits Story, Art { default String getTitle() { return "Book Title" ; }
}
Which set of class definitions compiles?

A. Interace story extends STnt {}
Interface Art extends SInt {}
B. Non-sealed interface story extends SInt {}
Non-sealed interaface Art extends Sint {}
C. Public interface story extends sInd {}
Public interface Art extends SInt {}
D. Sealed interface Storty extends sInt {}
Non-sealed class Art implements Sint {}
E. Non-sealed interface story extends SInt {}
Class Art implements Sint {}

Answer: D

Explanation:
Explanation
The answer is C because the code fragment given is an abstract sealed interface SInt that permits Story and Art. The correct answer is option C, which is a sealed interface Story that extends SInt and a non-sealed class Art that implements SInt. This is because a sealed interface can only be extended by the classes or interfaces that it permits, and a non-sealed class can implement a sealed interface.
Option A is incorrect because interface is misspelled as interace, and Story and Art should be capitalized as they are the names of the permitted classes or interfaces.
Option B is incorrect because public is misspelled as public, and sInd should be SInt as it is the name of the sealed interface.
Option D is incorrect because a non-sealed interface cannot extend a sealed interface, as it would violate the restriction of permitted subtypes.
Option E is incorrect because both Story and Art cannot be non-sealed interfaces, as they would also violate the restriction of permitted subtypes.
References:
Oracle Certified Professional: Java SE 17 Developer
Java SE 17 Developer
OCP Oracle Certified Professional Java SE 17 Developer Study Guide
Sealed Classes and Interfaces in Java 15 | Baeldung
Sealed Class in Java - Javatpoint

NEW QUESTION # 50
Which statement is true?

A. The lock () method returns a boolean indicator immediately if it has managed to acquire the lock, otherwise it waits for the lock acquisition.
B. The tryLock () method returns a boolean indicator immediately if it has managed to acquire the lock, otherwise it waits for the lock acquisition.
C. The tryLock () method returns a boolean indicator immediately regardless if it has or has not managed to acquire the lock.
D. The Lock () method returns a boolean indicator immediately regardless if it has or has not managed to acquire the lock

Answer: C

Explanation:
The tryLock () method of the Lock interface is a non-blocking attempt to acquire a lock. It returns true if the lock is available and acquired by the current thread, and false otherwise. It does not wait for the lock to be released by another thread. This is different from the lock () method, which blocks the current thread until the lock is acquired, and does not return any value. Reference: https://docs.oracle.com/en/java/javase/17/docs/api/java.base/java/util/concurrent/locks/Lock.html#tryLock(), 3, 4, 5

NEW QUESTION # 51
Which statement is true about migration?

A. The required modules migrate before the modules that depend on them in a top-down
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1Z0-829 LATEST EXAM NOTES, 1Z0-829 LATEST TEST DUMPS

1Z0-829 Latest Exam Notes, 1Z0-829 Latest Test Dumps